FACE
VALUE & PLACE VALUE :
FACE VALUE :
· Face value of a digit in a number is the
digit itself.
· Face value of a digit is always remains
the same irrespective of the position where it is located.
PLACE VALUE :
1. Each digit has a value depending on its place called the place value of the digit.
2. Place value of a digit = ( face value of the digit ) * ( value of the place ).
Example: Write the Face value and Place value of a
highlighted digit in the numbers.
1. 4,219
:
The Face value
of the digit 2 is 2.
The Place value
of the digit 2 is 200 .
(The digit 2 is in HUNDREDS place,so we have to multiply the digit 2 with its place value i.e; 100.Therefore the place value of the digit 2 becomes :
(The digit 2 is in HUNDREDS place,so we have to multiply the digit 2 with its place value i.e; 100.Therefore the place value of the digit 2 becomes :
digit * place value = 2 * 100 = 200) .
2. 7,641 :
The
Face value of the digit 4 is 4.
The
Place value of the digit 4 is 40.
( The digit 4 is in TENS place ,therefore the digit is to be multiplied with its place value i.e; 10.
( The digit 4 is in TENS place ,therefore the digit is to be multiplied with its place value i.e; 10.
Then the place value of the digit 4 becomes :
digit * place value = 4 * 10 = 40).
3. 90,263 :
The Face value of the digit 0 is 0.
The Place value of the digit 0 is 0.
In this number ,the place value of the digit 0 is also 0.
( The digit 0 is in THOUSANDS place.So, it is to be multiplied with its place value 1,000.
Therefore the place value of digit 0 becomes:
digit * place value = 0 * 1,000 = 0 ).
4. 8,62,134 :
The Face value of the digit 4 is 4.
The Place value of the digit 4 is 4.
( The digit 4 is in its ONES place.So, the digit 4 is multiplied with its place value : 1.
Therefore the place value of the digit 4 becomes :
digit * place value = 4 * 1 = 4 ) .
Note: The Face value & Place value of the digit in a number is the digit itself.
i: The digit in the number is ZERO .
ii: The digit is in its ONES place.
5. 7,51,695 :
The Face value of the digit 7 is 7 .
The place value of the digit 7 is 7,00,000.
( The digit 7 is in its LAKHS place.Then the digit is to be multiplied by its place value 1,00,000.
Note: The Face value & Place value of the digit in a number is the digit itself.
i: The digit in the number is ZERO .
ii: The digit is in its ONES place.
5. 7,51,695 :
The Face value of the digit 7 is 7 .
The place value of the digit 7 is 7,00,000.
( The digit 7 is in its LAKHS place.Then the digit is to be multiplied by its place value 1,00,000.
Therfore, the place value of the digit 7 becomes :
digit * place value = 7 * 1,00,000 = 7,00,000).
|
NUMBER |
PLACE VALUE |
FACE VALUE |
|
1346 |
3 * 100= 300 |
3 |
|
3359 |
9 * 1 = 9 |
9 |
|
7185 |
7 * 1000 = 7000 |
7 |
|
6666 |
6 * 10 = 60 |
6 |
|
8054 |
0 * 100 = 0 |
0 |
Man I'm pradyumnan . Can you give me a couple of questions on identities factorisation
ReplyDeleteOk, Pradyumnan.Posted some of the problems.
DeleteFactorise 2x^2+y^2+8z^2-2*root2xy+4root2yz-8zx
ReplyDeleteFactorize: 2x2 + y2 + 8z2 - 2√2 xy + 4√2 yz – 8zx
DeleteAnswer:
In the given expression 2x2 + y2 + 8z2 - 2√2 xy + 4√2 yz – 8zx
The number of variables are three : x , y ,z
By using the Square of a Trinomial : (a – b – c )2 = a2 + b2 + c2 – 2 ab + 2 bc – 2 ac
1st term : a2 = 2x2 ; a = √2 x
2 nd term : b2 = - 1 y2 ; b = - y
3rd term : c2 = - 8z2 ; c = - 2√2 z
4th term : 2ab = 2 * (√2 x) * (-y) = - 2 √2 xy
5th term : 2bc = 2 * ( - y ) * (- 2√2 z ) = 4√2 yz
6th term : 2ac = 2 * √2 x * (- 2√2 z ) = - 8zx
Therefore , the expression :
2x2 + y2 + 8z2 - 2√2 xy + 4√2 yz – 8zx is written as:
= (√2 x - y - 2√2 z )2
= (√2 x - y - 2√2 z)( √2 x - y - 2√2 z)
Square of trinomial Identity:
Delete(a + b + c )2 = a2 + b2 + c2 + 2 ab + 2 bc + 2 ac
Therefore;
(a – b – c )2
= a2 + (-b)2 + ( -c)2 + 2 * a * (-b) + 2 *(-b)*(-c) + 2 * a * (-c)
= a2 + b2 + c2 - 2 ab + 2 bc – 2 ac.